Rahul DubeyDropperSample· 29d ago
ΔG is zero at equilibrium but ΔG° = -RT ln K is not, why? Also, where's the third law?
Third attempt, and I still catch myself writing the wrong symbol in thermodynamics. Time to fix it at root. NCERT says that at equilibrium \Delta G = 0 . It also gives \Delta G^\circ = -RT\ln K . If \Delta G is zero at e
